How Can I Implement A Custom JqGrid Delete Button?
Solution 1:
You can use delGridRow method fore example. To do this you can just replace in your code jQuery('#list').deleteRow( to jQuery('#list').jqGrid('delGridRow',
You can consider to use formatter:'actions': see here, here and here. One more way to implement custom buttons you will find here.
UPDATED: To send additional information during Delete operation you can use delData parameter of delGridRow method:
be = "... onclick=\"jQuery('#list').deleteRow('" + cl +
",{delData:{Navn:'"+ jQuery("#list").jqGrid('getCell',cl,'Navn')+ "'});\" />";
The expression jQuery("#list").jqGrid('getCell',cl,'Navn') will get the value from the 'Navn' column and {delData:{Navn:'NavnValue'} will add Navn=NavnValue parameter to the data send to the server.
UPDATED 2: Your main problem was that you used in the demo project another version of the code as you posted in your question. Your demo has
... onclick=\"jQuery('#list').jqGrid('delGridRow','" + rows + "',
instead of
... onclick=\"jQuery('#list').jqGrid('delGridRow','" + cl + "',
which is the first important error. The rows variable you set as var rows = jQuery("#list").jqGrid('getGridParam','selrow'); inside of gridComplete. At the time no row is selected, rows = null and you place onclick=\"jQuery('#list').jqGrid('delGridRow','null' in for all your buttons.
The next important problem: you should rename
public ActionResult deleteRow(String ProductId)
to
public ActionResult deleteRow(String id)
or use prmNames: {id: 'ProductId'} as additional jqGrid parameter.
Other common problems:
- You should modify
_Layout.cshtmlfile. You should remove<script src="@Url.Content("~/Scripts/jquery-1.5.1.min.js")" type="text/javascript"></script>because you include another version of the jQuery (jquery-1.5.2.min.js) in theIndex.cshtml - You should close
<table id="list">(add ) in theIndex.cshtml. - If you want to have pager in the grid (you used
jQuery("#list").jqGrid('navGrid', "#page", ...) you should 1) add<div id="page"></div>in theIndex.cshtmland add parameterpager: '#page'to the jqGrid. - You have to clean the HTML markup which you use. For example you should remove
</div>from the end ofIndex.cshtml. One more</div>at the end of@RenderSection("Main", required: false)</div>(in the_Layout.cshtmlfile) should be also removed. To see the pager in the correct width you should include in the
_Layout.cshtmlfile the following fix<style type="text/css">input.ui-pg-input { width: auto; }</style>You should include at least jQuery UI CSS and
ui.jqgrid.cssfor example in the_Layout.cshtmlfile:
I would recommend you to replace jquery-1.5.2.min.js to jquery-1.6.2.min.js. The last version of vsdoc files you can always load from here. In the same way the last version (currently 1.8.16) of jQuery UI is also recommended.
I would recommend you to download the VS2010 demo project which I created for the answer and use it as the template for your project. You can easy change the code to use Razor.
Solution 2:
try
$("#classOfYourButton").click(function(e){
e.stopPropagation();
$(this).closest("tr").remove();
});
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