Bigint Issue Of Javascript

I want to find a sum of all integers of a large number for example power(99,95) I applied bigInt to get the power of large number and sum it together by below code. BigInt(Math.pow

Solution 1:

The expression Math.pow(99, 95), when it resolves, has already lost precision - casting it to a BigInt after the fact does not recover the lost precision.

Use BigInts from the beginning instead, and use ** instead of Math.pow so that the exponentiation works:

console.log(
  (99n ** 95n)
    .toString()
    .split('')
    .reduce((a, b) => a + Number(b), 0)
);

Solution 2:

BigInt(Math.pow(99,95))

This runs math pow on 2 floats, then converts it to bigint.

You want BigInt(99) ** BigInt(95) instead