Sorting Array With Decimal Value In Specific Order Using Javascript

I have an array: let arr = ['100.12', '100.8', '100.11', '100.9']; after sorting getting output: '100.11', '100.12', '100.8', '100.9', But I want it to be sorted like page indexi

Solution 1:

You can use string#localeCompare with numeric property to sort your array based on the numeric value.

let arr = ['100.12', '77.8', '88', '77.11', '77.12', '77.9', '77', '119', '120', '100.8', '100.11', '100', '100.9'];
arr.sort((a, b) => a.localeCompare(b, undefined, {numeric: true}))
console.log(arr)

Solution 2:

Not a simple oneliner. You wanna sort by the integer part first, then if that is equal, by the decimal part.

const arr =  ['100.12', '77.8', '88', '77.11', '77.12', '77.9', '77', '119', '120', '100.8', '100.11', '100', '100.9'];
const sorted = arr.sort((a, b) => {
      if (parseInt(a) !== parseInt(b)) {
        returnparseInt(a) - parseInt(b);
      }
      return (parseInt(a.split('.')[1], 10) || 0) - (parseInt(b.split('.')[1], 10) || 0);
    });
    
console.log(sorted);