{} - 0 Vs ({} - 0) In Javascript
Solution 1:
There are two possible interpretations of the line {} - 0:
- It can be interpreted as
{}; -0, where{}is interpreted as an empty block statement, and-is the unary negation operator (so-0is just "negative zero"). The value of this when evaluated is the value of the last statement, which is -0. - It can be interpreted as
({} - 0), where{}is interpreted as an empty object, and-is the subtraction operator (so0is subtracted from{}).
In your first line, this is ambiguous, so it will choose the first interpretation. In the second line, the first interpretation is invalid (as a block statement can never be part of an expression, which you're forcing with the parantheses).
Solution 2:
{} - 0: here {} is just an empty block that does nothing, so -0 returned by the console.
({} - 0): here {} is a part of expression and is converted to a number. There is no valueOf() method defined in that empty object and, while converting to a number, it falls back to toString() method which returns something like object Object for {}. Then this string object Object is being converted into a number and gives NaN since it is actually not a number. So, we've got
({} - 1) -> ('object Object' - 1) -> (NaN - 1)
and everything with NaN gives NaN. That's what you finally see in the console.
Solution 3:
{} - 0
is interpreted: {} empty block statement and - 0 negative zero
({} - 0)
all inside () is interpreted as an expression, empty object - 0 = NaN
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